(m-2)(m-2)=121

Solution for (m-2)(m-2)=121 equation:

(m-2)(m-2)=121

We move all terms to the left:

(m-2)(m-2)-(121)=0

We multiply parentheses ..

(+m^2-2m-2m+4)-121=0

We get rid of parentheses

m^2-2m-2m+4-121=0

We add all the numbers together, and all the variables

m^2-4m-117=0

a = 1; b = -4; c = -117;
Δ = b2-4ac
Δ = -42-4·1·(-117)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-22}{2*1}=\frac{-18}{2}
=-9
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+22}{2*1}=\frac{26}{2}
=13
$