(m+1)(2m+3)=0

Solution for (m+1)(2m+3)=0 equation:

Simplifying
(m + 1)(2m + 3) = 0

Reorder the terms:
(1 + m)(2m + 3) = 0

Reorder the terms:
(1 + m)(3 + 2m) = 0

Multiply (1 + m) * (3 + 2m)
(1(3 + 2m) + m(3 + 2m)) = 0
((3 * 1 + 2m * 1) + m(3 + 2m)) = 0
((3 + 2m) + m(3 + 2m)) = 0
(3 + 2m + (3 * m + 2m * m)) = 0
(3 + 2m + (3m + 2m2)) = 0

Combine like terms: 2m + 3m = 5m
(3 + 5m + 2m2) = 0

Solving
3 + 5m + 2m2 = 0

Solving for variable 'm'.

Factor a trinomial.
(3 + 2m)(1 + m) = 0

Subproblem 1
Set the factor '(3 + 2m)' equal to zero and attempt to solve:

Simplifying
3 + 2m = 0

Solving
3 + 2m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2m = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2m = 0 + -3
2m = 0 + -3

Combine like terms: 0 + -3 = -3
2m = -3

Divide each side by '2'.
m = -1.5

Simplifying
m = -1.5
Subproblem 2
Set the factor '(1 + m)' equal to zero and attempt to solve:

Simplifying
1 + m = 0

Solving
1 + m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + m = 0 + -1

Combine like terms: 1 + -1 = 0
0 + m = 0 + -1
m = 0 + -1

Combine like terms: 0 + -1 = -1
m = -1

Simplifying
m = -1
Solution
m = {-1.5, -1}