(lnx-1)(lnx+1)=0

Solution for (lnx-1)(lnx+1)=0 equation:

Simplifying
(lnx + -1)(lnx + 1) = 0

Reorder the terms:
(-1 + lnx)(lnx + 1) = 0

Reorder the terms:
(-1 + lnx)(1 + lnx) = 0

Multiply (-1 + lnx) * (1 + lnx)
(-1(1 + lnx) + lnx(1 + lnx)) = 0
((1 * -1 + lnx * -1) + lnx(1 + lnx)) = 0
((-1 + -1lnx) + lnx(1 + lnx)) = 0
(-1 + -1lnx + (1 * lnx + lnx * lnx)) = 0
(-1 + -1lnx + (1lnx + l2n2x2)) = 0

Combine like terms: -1lnx + 1lnx = 0
(-1 + 0 + l2n2x2) = 0
(-1 + l2n2x2) = 0

Solving
-1 + l2n2x2 = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + l2n2x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + l2n2x2 = 0 + 1
l2n2x2 = 0 + 1

Combine like terms: 0 + 1 = 1
l2n2x2 = 1

Divide each side by 'n2x2'.
l2 = n-2x-2

Simplifying
l2 = n-2x-2

Take the square root of each side:
l = {-1n-1x-1, n-1x-1}