(ln(0.5)/ln(1-x))=2

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Solution for (ln(0.5)/ln(1-x))=2 equation:


D( x )

ln(1-x) = 0

1-x <= 0

ln(1-x) = 0

ln(1-x) = 0

ln(1-x) = ln(e^0)

1-x = e^0

1-x-e^0 = 0

-1*x = 0 // : -1

x = 0

1-x <= 0

1-x <= 0

1-x <= 0

-x <= -1 // * -1

x >= 1

x in (-oo:0) U (0:1)

ln(0.5)/ln(1-x) = 2 // - 2

ln(0.5)/ln(1-x)-2 = 0

t_2 = ln(1-x)

ln(0.5)/t_2-2 = 0

ln(0.5)*t_2^-1 = 2 // : ln(0.5)

t_2^-1 = 2/ln(0.5)

-1 < 0

1/(t_2^1) = 2/ln(0.5) // * t_2^1

1 = (2/ln(0.5))*t_2^1 // : 2/ln(0.5)

1/(2/ln(0.5)) = t_2^1

t_2 = 1/(2/ln(0.5))

ln(1-x) = 1/(2/ln(0.5))

ln(1-x) = ln(e^(1/(2/ln(0.5))))

1-x = e^(1/(2/ln(0.5)))

1-x-e^(1/(2/ln(0.5))) = 0 // - 1-e^(1/(2/ln(0.5)))

-x = -(1-e^(1/(2/ln(0.5)))) // * -1

x = 1-e^(1/(2/ln(0.5)))

x = 1-e^(1/(2/ln(0.5)))

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