(k/56)=(12/7)

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Solution for (k/56)=(12/7) equation:



(k/56)=(12/7)
We move all terms to the left:
(k/56)-((12/7))=0
We add all the numbers together, and all the variables
(+k/56)-((+12/7))=0
We get rid of parentheses
k/56-((+12/7))=0
We calculate fractions
7k^2/()+()/()=0
We add all the numbers together, and all the variables
7k^2/()+1=0
We multiply all the terms by the denominator
7k^2+1*()=0
We add all the numbers together, and all the variables
7k^2=0
a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{14}=0$

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