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(k/5+3-3k=-6k
We move all terms to the left:
(k/5+3-3k-(-6k)=0
Domain of the equation: 5+3-3k-(-6k)!=0We multiply all the terms by the denominator
We move all terms containing k to the left, all other terms to the right
-3k-(-6k)!=-8
k∈R
(k=0
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