(k-4)(k+2)=0

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Solution for (k-4)(k+2)=0 equation:


Simplifying
(k + -4)(k + 2) = 0

Reorder the terms:
(-4 + k)(k + 2) = 0

Reorder the terms:
(-4 + k)(2 + k) = 0

Multiply (-4 + k) * (2 + k)
(-4(2 + k) + k(2 + k)) = 0
((2 * -4 + k * -4) + k(2 + k)) = 0
((-8 + -4k) + k(2 + k)) = 0
(-8 + -4k + (2 * k + k * k)) = 0
(-8 + -4k + (2k + k2)) = 0

Combine like terms: -4k + 2k = -2k
(-8 + -2k + k2) = 0

Solving
-8 + -2k + k2 = 0

Solving for variable 'k'.

Factor a trinomial.
(-2 + -1k)(4 + -1k) = 0

Subproblem 1

Set the factor '(-2 + -1k)' equal to zero and attempt to solve: Simplifying -2 + -1k = 0 Solving -2 + -1k = 0 Move all terms containing k to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1k = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1k = 0 + 2 -1k = 0 + 2 Combine like terms: 0 + 2 = 2 -1k = 2 Divide each side by '-1'. k = -2 Simplifying k = -2

Subproblem 2

Set the factor '(4 + -1k)' equal to zero and attempt to solve: Simplifying 4 + -1k = 0 Solving 4 + -1k = 0 Move all terms containing k to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1k = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1k = 0 + -4 -1k = 0 + -4 Combine like terms: 0 + -4 = -4 -1k = -4 Divide each side by '-1'. k = 4 Simplifying k = 4

Solution

k = {-2, 4}

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