(k-2)/5=11j

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Solution for (k-2)/5=11j equation: 


x in (-oo:+oo)

(k-2)/5 = 11*j // - 11*j

(k-2)/5-(11*j) = 0

(k-2)/5-11*j = 0

(k-2)/5+(-11*5*j)/5 = 0

k-11*5*j-2 = 0

k-55*j-2 = 0

(k-55*j-2)/5 = 0

(k-55*j-2)/5 = 0 // * 5

k-55*j-2 = 0

x belongs to the empty set

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