(k-1)/2=(k+3)/4

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Solution for (k-1)/2=(k+3)/4 equation: 



(k-1)/2=(k+3)/4

We move all terms to the left:

(k-1)/2-((k+3)/4)=0

We calculate fractions


k/()+(-((k+3)*2)/()=0



We calculate terms in parentheses: +(-((k+3)*2)/(), so:

-((k+3)*2)/(

We multiply all the terms by the denominator


-((k+3)*2)



We calculate terms in parentheses: -((k+3)*2), so:

(k+3)*2

We multiply parentheses

2k+6

Back to the equation:

-(2k+6)



We get rid of parentheses

-2k-6

Back to the equation:

+(-2k-6)



We get rid of parentheses

k/()-2k-6=0

We multiply all the terms by the denominator


k-2k*()-6*()=0

We add all the numbers together, and all the variables

k-2k*()=0

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