(k+2)/(5)=(2k-11)/(7)

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Solution for (k+2)/(5)=(2k-11)/(7) equation: 



(k+2)/(5)=(2k-11)/(7)

We move all terms to the left:

(k+2)/(5)-((2k-11)/(7))=0

We calculate fractions


k/()+(-((2k-11)*5)/()=0



We calculate terms in parentheses: +(-((2k-11)*5)/(), so:

-((2k-11)*5)/(

We multiply all the terms by the denominator


-((2k-11)*5)



We calculate terms in parentheses: -((2k-11)*5), so:

(2k-11)*5

We multiply parentheses

10k-55

Back to the equation:

-(10k-55)



We get rid of parentheses

-10k+55

Back to the equation:

+(-10k+55)



We get rid of parentheses

k/()-10k+55=0

We multiply all the terms by the denominator


k-10k*()+55*()=0

We add all the numbers together, and all the variables

k-10k*()=0

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