(k+2)-(3-K)=5

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Solution for (k+2)-(3-K)=5 equation:


Simplifying
(k + 2) + -1(3 + -1K) = 5

Reorder the terms:
(2 + k) + -1(3 + -1K) = 5

Remove parenthesis around (2 + k)
2 + k + -1(3 + -1K) = 5
2 + k + (3 * -1 + -1K * -1) = 5
2 + k + (-3 + 1K) = 5

Reorder the terms:
2 + -3 + 1K + k = 5

Combine like terms: 2 + -3 = -1
-1 + 1K + k = 5

Solving
-1 + 1K + k = 5

Solving for variable 'K'.

Move all terms containing K to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1K + 1 + k = 5 + 1

Reorder the terms:
-1 + 1 + 1K + k = 5 + 1

Combine like terms: -1 + 1 = 0
0 + 1K + k = 5 + 1
1K + k = 5 + 1

Combine like terms: 5 + 1 = 6
1K + k = 6

Add '-1k' to each side of the equation.
1K + k + -1k = 6 + -1k

Combine like terms: k + -1k = 0
1K + 0 = 6 + -1k
1K = 6 + -1k

Divide each side by '1'.
K = 6 + -1k

Simplifying
K = 6 + -1k

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