(k+2)*(-1)+(8-k)-k+1=-2

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Solution for (k+2)*(-1)+(8-k)-k+1=-2 equation: 



(k+2)(-1)+(8-k)-k+1=-2

We move all terms to the left:

(k+2)(-1)+(8-k)-k+1-(-2)=0

We add all the numbers together, and all the variables

(k+2)(-1)+(-1k+8)-k+1-(-2)=0

We add all the numbers together, and all the variables

-1k+(k+2)(-1)+(-1k+8)+3=0

We get rid of parentheses

-1k+(k+2)(-1)-1k+8+3=0

We multiply parentheses ..

-1k+(-1k-2)-1k+8+3=0

We add all the numbers together, and all the variables

-2k+(-1k-2)+11=0

We get rid of parentheses

-2k-1k-2+11=0

We add all the numbers together, and all the variables

-3k+9=0

We move all terms containing k to the left, all other terms to the right

-3k=-9

k=-9/-3

k=+3

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