(k+2)(k+4)=

Solution for (k+2)(k+4)= equation:

Simplifying
(k + 2)(k + 4) = 0

Reorder the terms:
(2 + k)(k + 4) = 0

Reorder the terms:
(2 + k)(4 + k) = 0

Multiply (2 + k) * (4 + k)
(2(4 + k) + k(4 + k)) = 0
((4 * 2 + k * 2) + k(4 + k)) = 0
((8 + 2k) + k(4 + k)) = 0
(8 + 2k + (4 * k + k * k)) = 0
(8 + 2k + (4k + k2)) = 0

Combine like terms: 2k + 4k = 6k
(8 + 6k + k2) = 0

Solving
8 + 6k + k2 = 0

Solving for variable 'k'.

Factor a trinomial.
(4 + k)(2 + k) = 0

Subproblem 1
Set the factor '(4 + k)' equal to zero and attempt to solve:

Simplifying
4 + k = 0

Solving
4 + k = 0

Move all terms containing k to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + k = 0 + -4

Combine like terms: 4 + -4 = 0
0 + k = 0 + -4
k = 0 + -4

Combine like terms: 0 + -4 = -4
k = -4

Simplifying
k = -4
Subproblem 2
Set the factor '(2 + k)' equal to zero and attempt to solve:

Simplifying
2 + k = 0

Solving
2 + k = 0

Move all terms containing k to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + k = 0 + -2

Combine like terms: 2 + -2 = 0
0 + k = 0 + -2
k = 0 + -2

Combine like terms: 0 + -2 = -2
k = -2

Simplifying
k = -2
Solution
k = {-4, -2}