(k+12)(k+10)=0

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Solution for (k+12)(k+10)=0 equation:


Simplifying
(k + 12)(k + 10) = 0

Reorder the terms:
(12 + k)(k + 10) = 0

Reorder the terms:
(12 + k)(10 + k) = 0

Multiply (12 + k) * (10 + k)
(12(10 + k) + k(10 + k)) = 0
((10 * 12 + k * 12) + k(10 + k)) = 0
((120 + 12k) + k(10 + k)) = 0
(120 + 12k + (10 * k + k * k)) = 0
(120 + 12k + (10k + k2)) = 0

Combine like terms: 12k + 10k = 22k
(120 + 22k + k2) = 0

Solving
120 + 22k + k2 = 0

Solving for variable 'k'.

Factor a trinomial.
(12 + k)(10 + k) = 0

Subproblem 1

Set the factor '(12 + k)' equal to zero and attempt to solve: Simplifying 12 + k = 0 Solving 12 + k = 0 Move all terms containing k to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + k = 0 + -12 Combine like terms: 12 + -12 = 0 0 + k = 0 + -12 k = 0 + -12 Combine like terms: 0 + -12 = -12 k = -12 Simplifying k = -12

Subproblem 2

Set the factor '(10 + k)' equal to zero and attempt to solve: Simplifying 10 + k = 0 Solving 10 + k = 0 Move all terms containing k to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + k = 0 + -10 Combine like terms: 10 + -10 = 0 0 + k = 0 + -10 k = 0 + -10 Combine like terms: 0 + -10 = -10 k = -10 Simplifying k = -10

Solution

k = {-12, -10}

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