(j-9)(j+2)=0

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Solution for (j-9)(j+2)=0 equation:


Simplifying
(j + -9)(j + 2) = 0

Reorder the terms:
(-9 + j)(j + 2) = 0

Reorder the terms:
(-9 + j)(2 + j) = 0

Multiply (-9 + j) * (2 + j)
(-9(2 + j) + j(2 + j)) = 0
((2 * -9 + j * -9) + j(2 + j)) = 0
((-18 + -9j) + j(2 + j)) = 0
(-18 + -9j + (2 * j + j * j)) = 0
(-18 + -9j + (2j + j2)) = 0

Combine like terms: -9j + 2j = -7j
(-18 + -7j + j2) = 0

Solving
-18 + -7j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-2 + -1j)(9 + -1j) = 0

Subproblem 1

Set the factor '(-2 + -1j)' equal to zero and attempt to solve: Simplifying -2 + -1j = 0 Solving -2 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1j = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1j = 0 + 2 -1j = 0 + 2 Combine like terms: 0 + 2 = 2 -1j = 2 Divide each side by '-1'. j = -2 Simplifying j = -2

Subproblem 2

Set the factor '(9 + -1j)' equal to zero and attempt to solve: Simplifying 9 + -1j = 0 Solving 9 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1j = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1j = 0 + -9 -1j = 0 + -9 Combine like terms: 0 + -9 = -9 -1j = -9 Divide each side by '-1'. j = 9 Simplifying j = 9

Solution

j = {-2, 9}

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