(j+3)+(3j-4)+(8-4j)=

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Solution for (j+3)+(3j-4)+(8-4j)= equation: 


Simplifying
(j + 3) + (3j + -4) + (8 + -4j) = 0

Reorder the terms:
(3 + j) + (3j + -4) + (8 + -4j) = 0

Remove parenthesis around (3 + j)
3 + j + (3j + -4) + (8 + -4j) = 0

Reorder the terms:
3 + j + (-4 + 3j) + (8 + -4j) = 0

Remove parenthesis around (-4 + 3j)
3 + j + -4 + 3j + (8 + -4j) = 0

Remove parenthesis around (8 + -4j)
3 + j + -4 + 3j + 8 + -4j = 0

Reorder the terms:
3 + -4 + 8 + j + 3j + -4j = 0

Combine like terms: 3 + -4 = -1
-1 + 8 + j + 3j + -4j = 0

Combine like terms: -1 + 8 = 7
7 + j + 3j + -4j = 0

Combine like terms: j + 3j = 4j
7 + 4j + -4j = 0

Combine like terms: 4j + -4j = 0
7 + 0 = 0
7 = 0

Solving
7 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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