(h-12)(h-5)=0

Solution for (h-12)(h-5)=0 equation:

Simplifying
(h + -12)(h + -5) = 0

Reorder the terms:
(-12 + h)(h + -5) = 0

Reorder the terms:
(-12 + h)(-5 + h) = 0

Multiply (-12 + h) * (-5 + h)
(-12(-5 + h) + h(-5 + h)) = 0
((-5 * -12 + h * -12) + h(-5 + h)) = 0
((60 + -12h) + h(-5 + h)) = 0
(60 + -12h + (-5 * h + h * h)) = 0
(60 + -12h + (-5h + h2)) = 0

Combine like terms: -12h + -5h = -17h
(60 + -17h + h2) = 0

Solving
60 + -17h + h2 = 0

Solving for variable 'h'.

Factor a trinomial.
(5 + -1h)(12 + -1h) = 0

Subproblem 1
Set the factor '(5 + -1h)' equal to zero and attempt to solve:

Simplifying
5 + -1h = 0

Solving
5 + -1h = 0

Move all terms containing h to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1h = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1h = 0 + -5
-1h = 0 + -5

Combine like terms: 0 + -5 = -5
-1h = -5

Divide each side by '-1'.
h = 5

Simplifying
h = 5
Subproblem 2
Set the factor '(12 + -1h)' equal to zero and attempt to solve:

Simplifying
12 + -1h = 0

Solving
12 + -1h = 0

Move all terms containing h to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1h = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1h = 0 + -12
-1h = 0 + -12

Combine like terms: 0 + -12 = -12
-1h = -12

Divide each side by '-1'.
h = 12

Simplifying
h = 12
Solution
h = {5, 12}