(h+2)+(h+2)+(h+2)+(h+2)+(h+2)=20

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Solution for (h+2)+(h+2)+(h+2)+(h+2)+(h+2)=20 equation: 



(h+2)+(h+2)+(h+2)+(h+2)+(h+2)=20

We move all terms to the left:

(h+2)+(h+2)+(h+2)+(h+2)+(h+2)-(20)=0

We get rid of parentheses

h+h+h+h+h+2+2+2+2+2-20=0

We add all the numbers together, and all the variables

5h-10=0

We move all terms containing h to the left, all other terms to the right

5h=10

h=10/5

h=2

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