(g+4-3g=1+g)

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Solution for (g+4-3g=1+g) equation: 



(g+4-3g=1+g)

We move all terms to the left:

(g+4-3g-(1+g))=0

We add all the numbers together, and all the variables

(g+4-3g-(g+1))=0



We calculate terms in parentheses: +(g+4-3g-(g+1)), so:

g+4-3g-(g+1)

determiningTheFunctionDomain
g-3g-(g+1)+4

We add all the numbers together, and all the variables

-2g-(g+1)+4

We get rid of parentheses

-2g-g-1+4

We add all the numbers together, and all the variables

-3g+3

Back to the equation:

+(-3g+3)



We get rid of parentheses

-3g+3=0

We move all terms containing g to the left, all other terms to the right

-3g=-3

g=-3/-3

g=1

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