(f-5)(f+1)=(f+3)(f+70

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Solution for (f-5)(f+1)=(f+3)(f+70 equation: 



(f-5)(f+1)=(f+3)(f+70

We move all terms to the left:

(f-5)(f+1)-((f+3)(f+70)=0

We multiply parentheses ..

(+f^2+f-5f-5)-((f+3)(f+70)=0



We calculate terms in parentheses: -((f+3)(f+70), so:

(f+3)(f+70



We get rid of parentheses

f^2+f-5f-((f+3)(f+70)-5=0

We multiply parentheses ..

f^2-((+f^2+70f+3f+210)-5+f-5f=0

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