(e+1)(e-12)=

Solution for (e+1)(e-12)= equation:

Simplifying
(e + 1)(e + -12) = 0

Reorder the terms:
(1 + e)(e + -12) = 0

Reorder the terms:
(1 + e)(-12 + e) = 0

Multiply (1 + e) * (-12 + e)
(1(-12 + e) + e(-12 + e)) = 0
((-12 * 1 + e * 1) + e(-12 + e)) = 0
((-12 + 1e) + e(-12 + e)) = 0
(-12 + 1e + (-12 * e + e * e)) = 0
(-12 + 1e + (-12e + e2)) = 0

Combine like terms: 1e + -12e = -11e
(-12 + -11e + e2) = 0

Solving
-12 + -11e + e2 = 0

Solving for variable 'e'.

Factor a trinomial.
(-1 + -1e)(12 + -1e) = 0

Subproblem 1
Set the factor '(-1 + -1e)' equal to zero and attempt to solve:

Simplifying
-1 + -1e = 0

Solving
-1 + -1e = 0

Move all terms containing e to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1e = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1e = 0 + 1
-1e = 0 + 1

Combine like terms: 0 + 1 = 1
-1e = 1

Divide each side by '-1'.
e = -1

Simplifying
e = -1
Subproblem 2
Set the factor '(12 + -1e)' equal to zero and attempt to solve:

Simplifying
12 + -1e = 0

Solving
12 + -1e = 0

Move all terms containing e to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1e = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1e = 0 + -12
-1e = 0 + -12

Combine like terms: 0 + -12 = -12
-1e = -12

Divide each side by '-1'.
e = 12

Simplifying
e = 12
Solution
e = {-1, 12}