(d-b)(d+b)=

Solution for (d-b)(d+b)= equation:

Simplifying
(d + -1b)(d + b) = 0

Reorder the terms:
(-1b + d)(d + b) = 0

Reorder the terms:
(-1b + d)(b + d) = 0

Multiply (-1b + d) * (b + d)
(-1b * (b + d) + d(b + d)) = 0
((b * -1b + d * -1b) + d(b + d)) = 0

Reorder the terms:
((-1bd + -1b2) + d(b + d)) = 0
((-1bd + -1b2) + d(b + d)) = 0
(-1bd + -1b2 + (b * d + d * d)) = 0
(-1bd + -1b2 + (bd + d2)) = 0

Reorder the terms:
(-1bd + bd + -1b2 + d2) = 0

Combine like terms: -1bd + bd = 0
(0 + -1b2 + d2) = 0
(-1b2 + d2) = 0

Solving
-1b2 + d2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1d2' to each side of the equation.
-1b2 + d2 + -1d2 = 0 + -1d2

Combine like terms: d2 + -1d2 = 0
-1b2 + 0 = 0 + -1d2
-1b2 = 0 + -1d2
Remove the zero:
-1b2 = -1d2

Divide each side by '-1'.
b2 = d2

Simplifying
b2 = d2

Take the square root of each side:
b = {-1d, d}