(d+4)(d+2)=0

Solution for (d+4)(d+2)=0 equation:

Simplifying
(d + 4)(d + 2) = 0

Reorder the terms:
(4 + d)(d + 2) = 0

Reorder the terms:
(4 + d)(2 + d) = 0

Multiply (4 + d) * (2 + d)
(4(2 + d) + d(2 + d)) = 0
((2 * 4 + d * 4) + d(2 + d)) = 0
((8 + 4d) + d(2 + d)) = 0
(8 + 4d + (2 * d + d * d)) = 0
(8 + 4d + (2d + d2)) = 0

Combine like terms: 4d + 2d = 6d
(8 + 6d + d2) = 0

Solving
8 + 6d + d2 = 0

Solving for variable 'd'.

Factor a trinomial.
(4 + d)(2 + d) = 0

Subproblem 1
Set the factor '(4 + d)' equal to zero and attempt to solve:

Simplifying
4 + d = 0

Solving
4 + d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + d = 0 + -4

Combine like terms: 4 + -4 = 0
0 + d = 0 + -4
d = 0 + -4

Combine like terms: 0 + -4 = -4
d = -4

Simplifying
d = -4
Subproblem 2
Set the factor '(2 + d)' equal to zero and attempt to solve:

Simplifying
2 + d = 0

Solving
2 + d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + d = 0 + -2

Combine like terms: 2 + -2 = 0
0 + d = 0 + -2
d = 0 + -2

Combine like terms: 0 + -2 = -2
d = -2

Simplifying
d = -2
Solution
d = {-4, -2}