(d+2)(d+2)=0

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Solution for (d+2)(d+2)=0 equation: 



(d+2)(d+2)=0

We multiply parentheses ..

(+d^2+2d+2d+4)=0

We get rid of parentheses

d^2+2d+2d+4=0

We add all the numbers together, and all the variables

d^2+4d+4=0

a = 1; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{-4}{2}=-2$

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