(d+2)(d+10)=0

Solution for (d+2)(d+10)=0 equation:

Simplifying
(d + 2)(d + 10) = 0

Reorder the terms:
(2 + d)(d + 10) = 0

Reorder the terms:
(2 + d)(10 + d) = 0

Multiply (2 + d) * (10 + d)
(2(10 + d) + d(10 + d)) = 0
((10 * 2 + d * 2) + d(10 + d)) = 0
((20 + 2d) + d(10 + d)) = 0
(20 + 2d + (10 * d + d * d)) = 0
(20 + 2d + (10d + d2)) = 0

Combine like terms: 2d + 10d = 12d
(20 + 12d + d2) = 0

Solving
20 + 12d + d2 = 0

Solving for variable 'd'.

Factor a trinomial.
(10 + d)(2 + d) = 0

Subproblem 1
Set the factor '(10 + d)' equal to zero and attempt to solve:

Simplifying
10 + d = 0

Solving
10 + d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + d = 0 + -10

Combine like terms: 10 + -10 = 0
0 + d = 0 + -10
d = 0 + -10

Combine like terms: 0 + -10 = -10
d = -10

Simplifying
d = -10
Subproblem 2
Set the factor '(2 + d)' equal to zero and attempt to solve:

Simplifying
2 + d = 0

Solving
2 + d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + d = 0 + -2

Combine like terms: 2 + -2 = 0
0 + d = 0 + -2
d = 0 + -2

Combine like terms: 0 + -2 = -2
d = -2

Simplifying
d = -2
Solution
d = {-10, -2}