(d+1)+(d+1)+(d+1)=64

Solution for (d+1)+(d+1)+(d+1)=64 equation:

Simplifying
(d + 1) + (d + 1) + (d + 1) = 64

Reorder the terms:
(1 + d) + (d + 1) + (d + 1) = 64

Remove parenthesis around (1 + d)
1 + d + (d + 1) + (d + 1) = 64

Reorder the terms:
1 + d + (1 + d) + (d + 1) = 64

Remove parenthesis around (1 + d)
1 + d + 1 + d + (d + 1) = 64

Reorder the terms:
1 + d + 1 + d + (1 + d) = 64

Remove parenthesis around (1 + d)
1 + d + 1 + d + 1 + d = 64

Reorder the terms:
1 + 1 + 1 + d + d + d = 64

Combine like terms: 1 + 1 = 2
2 + 1 + d + d + d = 64

Combine like terms: 2 + 1 = 3
3 + d + d + d = 64

Combine like terms: d + d = 2d
3 + 2d + d = 64

Combine like terms: 2d + d = 3d
3 + 3d = 64

Solving
3 + 3d = 64

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3d = 64 + -3

Combine like terms: 3 + -3 = 0
0 + 3d = 64 + -3
3d = 64 + -3

Combine like terms: 64 + -3 = 61
3d = 61

Divide each side by '3'.
d = 20.33333333

Simplifying
d = 20.33333333