(c-9)=9(2c-8)+4c

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Solution for (c-9)=9(2c-8)+4c equation: 



(c-9)=9(2c-8)+4c

We move all terms to the left:

(c-9)-(9(2c-8)+4c)=0

We get rid of parentheses

c-(9(2c-8)+4c)-9=0



We calculate terms in parentheses: -(9(2c-8)+4c), so:

9(2c-8)+4c

We add all the numbers together, and all the variables

4c+9(2c-8)

We multiply parentheses

4c+18c-72

We add all the numbers together, and all the variables

22c-72

Back to the equation:

-(22c-72)



We get rid of parentheses

c-22c+72-9=0

We add all the numbers together, and all the variables

-21c+63=0

We move all terms containing c to the left, all other terms to the right

-21c=-63

c=-63/-21

c=+3

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