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Simplifying (c + -9)(c + 25) = 0 Reorder the terms: (-9 + c)(c + 25) = 0 Reorder the terms: (-9 + c)(25 + c) = 0 Multiply (-9 + c) * (25 + c) (-9(25 + c) + c(25 + c)) = 0 ((25 * -9 + c * -9) + c(25 + c)) = 0 ((-225 + -9c) + c(25 + c)) = 0 (-225 + -9c + (25 * c + c * c)) = 0 (-225 + -9c + (25c + c2)) = 0 Combine like terms: -9c + 25c = 16c (-225 + 16c + c2) = 0 Solving -225 + 16c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (-25 + -1c)(9 + -1c) = 0Subproblem 1
Set the factor '(-25 + -1c)' equal to zero and attempt to solve: Simplifying -25 + -1c = 0 Solving -25 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '25' to each side of the equation. -25 + 25 + -1c = 0 + 25 Combine like terms: -25 + 25 = 0 0 + -1c = 0 + 25 -1c = 0 + 25 Combine like terms: 0 + 25 = 25 -1c = 25 Divide each side by '-1'. c = -25 Simplifying c = -25Subproblem 2
Set the factor '(9 + -1c)' equal to zero and attempt to solve: Simplifying 9 + -1c = 0 Solving 9 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1c = 0 + -9 -1c = 0 + -9 Combine like terms: 0 + -9 = -9 -1c = -9 Divide each side by '-1'. c = 9 Simplifying c = 9Solution
c = {-25, 9}
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