(c-3)(c-3)=0

Solution for (c-3)(c-3)=0 equation:

Simplifying
(c + -3)(c + -3) = 0

Reorder the terms:
(-3 + c)(c + -3) = 0

Reorder the terms:
(-3 + c)(-3 + c) = 0

Multiply (-3 + c) * (-3 + c)
(-3(-3 + c) + c(-3 + c)) = 0
((-3 * -3 + c * -3) + c(-3 + c)) = 0
((9 + -3c) + c(-3 + c)) = 0
(9 + -3c + (-3 * c + c * c)) = 0
(9 + -3c + (-3c + c2)) = 0

Combine like terms: -3c + -3c = -6c
(9 + -6c + c2) = 0

Solving
9 + -6c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + -1c)(3 + -1c) = 0

Subproblem 1
Set the factor '(3 + -1c)' equal to zero and attempt to solve:

Simplifying
3 + -1c = 0

Solving
3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1c = 0 + -3
-1c = 0 + -3

Combine like terms: 0 + -3 = -3
-1c = -3

Divide each side by '-1'.
c = 3

Simplifying
c = 3
Subproblem 2
Set the factor '(3 + -1c)' equal to zero and attempt to solve:

Simplifying
3 + -1c = 0

Solving
3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1c = 0 + -3
-1c = 0 + -3

Combine like terms: 0 + -3 = -3
-1c = -3

Divide each side by '-1'.
c = 3

Simplifying
c = 3
Solution
c = {3, 3}