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(c-13)+(4c-11)+(c)=180
We move all terms to the left:
(c-13)+(4c-11)+(c)-(180)=0
We add all the numbers together, and all the variables
c+(c-13)+(4c-11)-180=0
We get rid of parentheses
c+c+4c-13-11-180=0
We add all the numbers together, and all the variables
6c-204=0
We move all terms containing c to the left, all other terms to the right
6c=204
c=204/6
c=34
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