(c-1)*(3-c)=0

Solution for (c-1)*(3-c)=0 equation:

Simplifying
(c + -1)(3 + -1c) = 0

Reorder the terms:
(-1 + c)(3 + -1c) = 0

Multiply (-1 + c) * (3 + -1c)
(-1(3 + -1c) + c(3 + -1c)) = 0
((3 * -1 + -1c * -1) + c(3 + -1c)) = 0
((-3 + 1c) + c(3 + -1c)) = 0
(-3 + 1c + (3 * c + -1c * c)) = 0
(-3 + 1c + (3c + -1c2)) = 0

Combine like terms: 1c + 3c = 4c
(-3 + 4c + -1c2) = 0

Solving
-3 + 4c + -1c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + c)(1 + -1c) = 0

Subproblem 1
Set the factor '(-3 + c)' equal to zero and attempt to solve:

Simplifying
-3 + c = 0

Solving
-3 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + c = 0 + 3

Combine like terms: -3 + 3 = 0
0 + c = 0 + 3
c = 0 + 3

Combine like terms: 0 + 3 = 3
c = 3

Simplifying
c = 3
Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve:

Simplifying
1 + -1c = 0

Solving
1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c = 0 + -1
-1c = 0 + -1

Combine like terms: 0 + -1 = -1
-1c = -1

Divide each side by '-1'.
c = 1

Simplifying
c = 1
Solution
c = {3, 1}