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(c+6)(c+6)=0
We multiply parentheses ..
(+c^2+6c+6c+36)=0
We get rid of parentheses
c^2+6c+6c+36=0
We add all the numbers together, and all the variables
c^2+12c+36=0
a = 1; b = 12; c = +36;
Δ = b2-4ac
Δ = 122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$c=\frac{-b}{2a}=\frac{-12}{2}=-6$
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