(c+5)(c-5)=0

Solution for (c+5)(c-5)=0 equation:

Simplifying
(c + 5)(c + -5) = 0

Reorder the terms:
(5 + c)(c + -5) = 0

Reorder the terms:
(5 + c)(-5 + c) = 0

Multiply (5 + c) * (-5 + c)
(5(-5 + c) + c(-5 + c)) = 0
((-5 * 5 + c * 5) + c(-5 + c)) = 0
((-25 + 5c) + c(-5 + c)) = 0
(-25 + 5c + (-5 * c + c * c)) = 0
(-25 + 5c + (-5c + c2)) = 0

Combine like terms: 5c + -5c = 0
(-25 + 0 + c2) = 0
(-25 + c2) = 0

Solving
-25 + c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + c2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + c2 = 0 + 25
c2 = 0 + 25

Combine like terms: 0 + 25 = 25
c2 = 25

Simplifying
c2 = 25

Take the square root of each side:
c = {-5, 5}