(c+4)(c-2)=0

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Solution for (c+4)(c-2)=0 equation:


Simplifying
(c + 4)(c + -2) = 0

Reorder the terms:
(4 + c)(c + -2) = 0

Reorder the terms:
(4 + c)(-2 + c) = 0

Multiply (4 + c) * (-2 + c)
(4(-2 + c) + c(-2 + c)) = 0
((-2 * 4 + c * 4) + c(-2 + c)) = 0
((-8 + 4c) + c(-2 + c)) = 0
(-8 + 4c + (-2 * c + c * c)) = 0
(-8 + 4c + (-2c + c2)) = 0

Combine like terms: 4c + -2c = 2c
(-8 + 2c + c2) = 0

Solving
-8 + 2c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-4 + -1c)(2 + -1c) = 0

Subproblem 1

Set the factor '(-4 + -1c)' equal to zero and attempt to solve: Simplifying -4 + -1c = 0 Solving -4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1c = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1c = 0 + 4 -1c = 0 + 4 Combine like terms: 0 + 4 = 4 -1c = 4 Divide each side by '-1'. c = -4 Simplifying c = -4

Subproblem 2

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {-4, 2}

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