(c+3)-2c-2(1-3c)=2

Solution for (c+3)-2c-2(1-3c)=2 equation:

Simplifying
(c + 3) + -2c + -2(1 + -3c) = 2

Reorder the terms:
(3 + c) + -2c + -2(1 + -3c) = 2

Remove parenthesis around (3 + c)
3 + c + -2c + -2(1 + -3c) = 2
3 + c + -2c + (1 * -2 + -3c * -2) = 2
3 + c + -2c + (-2 + 6c) = 2

Reorder the terms:
3 + -2 + c + -2c + 6c = 2

Combine like terms: 3 + -2 = 1
1 + c + -2c + 6c = 2

Combine like terms: c + -2c = -1c
1 + -1c + 6c = 2

Combine like terms: -1c + 6c = 5c
1 + 5c = 2

Solving
1 + 5c = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 5c = 2 + -1

Combine like terms: 1 + -1 = 0
0 + 5c = 2 + -1
5c = 2 + -1

Combine like terms: 2 + -1 = 1
5c = 1

Divide each side by '5'.
c = 0.2

Simplifying
c = 0.2