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Simplifying (c + 3)(c + 3) = 16 Reorder the terms: (3 + c)(c + 3) = 16 Reorder the terms: (3 + c)(3 + c) = 16 Multiply (3 + c) * (3 + c) (3(3 + c) + c(3 + c)) = 16 ((3 * 3 + c * 3) + c(3 + c)) = 16 ((9 + 3c) + c(3 + c)) = 16 (9 + 3c + (3 * c + c * c)) = 16 (9 + 3c + (3c + c2)) = 16 Combine like terms: 3c + 3c = 6c (9 + 6c + c2) = 16 Solving 9 + 6c + c2 = 16 Solving for variable 'c'. Reorder the terms: 9 + -16 + 6c + c2 = 16 + -16 Combine like terms: 9 + -16 = -7 -7 + 6c + c2 = 16 + -16 Combine like terms: 16 + -16 = 0 -7 + 6c + c2 = 0 Factor a trinomial. (-7 + -1c)(1 + -1c) = 0Subproblem 1
Set the factor '(-7 + -1c)' equal to zero and attempt to solve: Simplifying -7 + -1c = 0 Solving -7 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1c = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1c = 0 + 7 -1c = 0 + 7 Combine like terms: 0 + 7 = 7 -1c = 7 Divide each side by '-1'. c = -7 Simplifying c = -7Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1Solution
c = {-7, 1}
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