(c+3)(c+3)+25=0

Solution for (c+3)(c+3)+25=0 equation:

Simplifying
(c + 3)(c + 3) + 25 = 0

Reorder the terms:
(3 + c)(c + 3) + 25 = 0

Reorder the terms:
(3 + c)(3 + c) + 25 = 0

Multiply (3 + c) * (3 + c)
(3(3 + c) + c(3 + c)) + 25 = 0
((3 * 3 + c * 3) + c(3 + c)) + 25 = 0
((9 + 3c) + c(3 + c)) + 25 = 0
(9 + 3c + (3 * c + c * c)) + 25 = 0
(9 + 3c + (3c + c2)) + 25 = 0

Combine like terms: 3c + 3c = 6c
(9 + 6c + c2) + 25 = 0

Reorder the terms:
9 + 25 + 6c + c2 = 0

Combine like terms: 9 + 25 = 34
34 + 6c + c2 = 0

Solving
34 + 6c + c2 = 0

Solving for variable 'c'.

Begin completing the square.

Move the constant term to the right:

Add '-34' to each side of the equation.
34 + 6c + -34 + c2 = 0 + -34

Reorder the terms:
34 + -34 + 6c + c2 = 0 + -34

Combine like terms: 34 + -34 = 0
0 + 6c + c2 = 0 + -34
6c + c2 = 0 + -34

Combine like terms: 0 + -34 = -34
6c + c2 = -34

The c term is 6c.  Take half its coefficient (3).
Square it (9) and add it to both sides.

Add '9' to each side of the equation.
6c + 9 + c2 = -34 + 9

Reorder the terms:
9 + 6c + c2 = -34 + 9

Combine like terms: -34 + 9 = -25
9 + 6c + c2 = -25

Factor a perfect square on the left side:
(c + 3)(c + 3) = -25

Can't calculate square root of the right side.

The solution to this equation could not be determined.