(c+3)(c+2)=0

Solution for (c+3)(c+2)=0 equation:

Simplifying
(c + 3)(c + 2) = 0

Reorder the terms:
(3 + c)(c + 2) = 0

Reorder the terms:
(3 + c)(2 + c) = 0

Multiply (3 + c) * (2 + c)
(3(2 + c) + c(2 + c)) = 0
((2 * 3 + c * 3) + c(2 + c)) = 0
((6 + 3c) + c(2 + c)) = 0
(6 + 3c + (2 * c + c * c)) = 0
(6 + 3c + (2c + c2)) = 0

Combine like terms: 3c + 2c = 5c
(6 + 5c + c2) = 0

Solving
6 + 5c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + c)(2 + c) = 0

Subproblem 1
Set the factor '(3 + c)' equal to zero and attempt to solve:

Simplifying
3 + c = 0

Solving
3 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + c = 0 + -3
c = 0 + -3

Combine like terms: 0 + -3 = -3
c = -3

Simplifying
c = -3
Subproblem 2
Set the factor '(2 + c)' equal to zero and attempt to solve:

Simplifying
2 + c = 0

Solving
2 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + c = 0 + -2
c = 0 + -2

Combine like terms: 0 + -2 = -2
c = -2

Simplifying
c = -2
Solution
c = {-3, -2}