(c+1)+3C+48=180

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Solution for (c+1)+3C+48=180 equation:


Simplifying
(c + 1) + 3C + 48 = 180

Reorder the terms:
(1 + c) + 3C + 48 = 180

Remove parenthesis around (1 + c)
1 + c + 3C + 48 = 180

Reorder the terms:
1 + 48 + 3C + c = 180

Combine like terms: 1 + 48 = 49
49 + 3C + c = 180

Solving
49 + 3C + c = 180

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-49' to each side of the equation.
49 + 3C + -49 + c = 180 + -49

Reorder the terms:
49 + -49 + 3C + c = 180 + -49

Combine like terms: 49 + -49 = 0
0 + 3C + c = 180 + -49
3C + c = 180 + -49

Combine like terms: 180 + -49 = 131
3C + c = 131

Add '-1c' to each side of the equation.
3C + c + -1c = 131 + -1c

Combine like terms: c + -1c = 0
3C + 0 = 131 + -1c
3C = 131 + -1c

Divide each side by '3'.
C = 43.66666667 + -0.3333333333c

Simplifying
C = 43.66666667 + -0.3333333333c

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