(c+1)(c-1)=0

Solution for (c+1)(c-1)=0 equation:

Simplifying
(c + 1)(c + -1) = 0

Reorder the terms:
(1 + c)(c + -1) = 0

Reorder the terms:
(1 + c)(-1 + c) = 0

Multiply (1 + c) * (-1 + c)
(1(-1 + c) + c(-1 + c)) = 0
((-1 * 1 + c * 1) + c(-1 + c)) = 0
((-1 + 1c) + c(-1 + c)) = 0
(-1 + 1c + (-1 * c + c * c)) = 0
(-1 + 1c + (-1c + c2)) = 0

Combine like terms: 1c + -1c = 0
(-1 + 0 + c2) = 0
(-1 + c2) = 0

Solving
-1 + c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + c2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + c2 = 0 + 1
c2 = 0 + 1

Combine like terms: 0 + 1 = 1
c2 = 1

Simplifying
c2 = 1

Take the square root of each side:
c = {-1, 1}