(c+1)(c+5)=0

Solution for (c+1)(c+5)=0 equation:

Simplifying
(c + 1)(c + 5) = 0

Reorder the terms:
(1 + c)(c + 5) = 0

Reorder the terms:
(1 + c)(5 + c) = 0

Multiply (1 + c) * (5 + c)
(1(5 + c) + c(5 + c)) = 0
((5 * 1 + c * 1) + c(5 + c)) = 0
((5 + 1c) + c(5 + c)) = 0
(5 + 1c + (5 * c + c * c)) = 0
(5 + 1c + (5c + c2)) = 0

Combine like terms: 1c + 5c = 6c
(5 + 6c + c2) = 0

Solving
5 + 6c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + c)(1 + c) = 0

Subproblem 1
Set the factor '(5 + c)' equal to zero and attempt to solve:

Simplifying
5 + c = 0

Solving
5 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + c = 0 + -5
c = 0 + -5

Combine like terms: 0 + -5 = -5
c = -5

Simplifying
c = -5
Subproblem 2
Set the factor '(1 + c)' equal to zero and attempt to solve:

Simplifying
1 + c = 0

Solving
1 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + c = 0 + -1
c = 0 + -1

Combine like terms: 0 + -1 = -1
c = -1

Simplifying
c = -1
Solution
c = {-5, -1}