(bx-cy)dy+(ax-by)dx=0

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Solution for (bx-cy)dy+(ax-by)dx=0 equation:


Simplifying
(bx + -1cy) * dy + (ax + -1by) * dx = 0

Reorder the terms for easier multiplication:
dy(bx + -1cy) + (ax + -1by) * dx = 0
(bx * dy + -1cy * dy) + (ax + -1by) * dx = 0
(bdxy + -1cdy2) + (ax + -1by) * dx = 0

Reorder the terms for easier multiplication:
bdxy + -1cdy2 + dx(ax + -1by) = 0
bdxy + -1cdy2 + (ax * dx + -1by * dx) = 0
bdxy + -1cdy2 + (adx2 + -1bdxy) = 0

Reorder the terms:
adx2 + bdxy + -1bdxy + -1cdy2 = 0

Combine like terms: bdxy + -1bdxy = 0
adx2 + 0 + -1cdy2 = 0
adx2 + -1cdy2 = 0

Solving
adx2 + -1cdy2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'cdy2' to each side of the equation.
adx2 + -1cdy2 + cdy2 = 0 + cdy2

Combine like terms: -1cdy2 + cdy2 = 0
adx2 + 0 = 0 + cdy2
adx2 = 0 + cdy2
Remove the zero:
adx2 = cdy2

Divide each side by 'dx2'.
a = cx-2y2

Simplifying
a = cx-2y2

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