(b-8)-5=9(b+2)+1

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Solution for (b-8)-5=9(b+2)+1 equation:


(b-8)-5=9(b+2)+1

We simplify the equation to the form, which is simple to understand 
(b-8)-5=9(b+2)+1

Remove unnecessary parentheses
b-8-5=9*(b+2)+1

Reorder the terms in parentheses
b-8-5=+(+9b+18)+1

Remove unnecessary parentheses
+b-8-5=+9b+18+1

We move all terms containing b to the left and all other terms to the right. 
+1b-9b=+18+1+8+5

We simplify left and right side of the equation. 
-8b=+32

We divide both sides of the equation by -8 to get b. 
b=-4

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