(b-8)+b+(4(b-8))=26

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Solution for (b-8)+b+(4(b-8))=26 equation:


Simplifying
(b + -8) + b + (4(b + -8)) = 26

Reorder the terms:
(-8 + b) + b + (4(b + -8)) = 26

Remove parenthesis around (-8 + b)
-8 + b + b + (4(b + -8)) = 26

Reorder the terms:
-8 + b + b + (4(-8 + b)) = 26
-8 + b + b + ((-8 * 4 + b * 4)) = 26
-8 + b + b + ((-32 + 4b)) = 26
-8 + b + b + (-32 + 4b) = 26

Remove parenthesis around (-32 + 4b)
-8 + b + b + -32 + 4b = 26

Reorder the terms:
-8 + -32 + b + b + 4b = 26

Combine like terms: -8 + -32 = -40
-40 + b + b + 4b = 26

Combine like terms: b + b = 2b
-40 + 2b + 4b = 26

Combine like terms: 2b + 4b = 6b
-40 + 6b = 26

Solving
-40 + 6b = 26

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '40' to each side of the equation.
-40 + 40 + 6b = 26 + 40

Combine like terms: -40 + 40 = 0
0 + 6b = 26 + 40
6b = 26 + 40

Combine like terms: 26 + 40 = 66
6b = 66

Divide each side by '6'.
b = 11

Simplifying
b = 11

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