(b-6)/3=(b+7)/2

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Solution for (b-6)/3=(b+7)/2 equation: 



(b-6)/3=(b+7)/2

We move all terms to the left:

(b-6)/3-((b+7)/2)=0

We calculate fractions


b/()+(-((b+7)*3)/()=0



We calculate terms in parentheses: +(-((b+7)*3)/(), so:

-((b+7)*3)/(

We multiply all the terms by the denominator


-((b+7)*3)



We calculate terms in parentheses: -((b+7)*3), so:

(b+7)*3

We multiply parentheses

3b+21

Back to the equation:

-(3b+21)



We get rid of parentheses

-3b-21

Back to the equation:

+(-3b-21)



We get rid of parentheses

b/()-3b-21=0

We multiply all the terms by the denominator


b-3b*()-21*()=0

We add all the numbers together, and all the variables

b-3b*()=0

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