(b-5)/7=3

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Solution for (b-5)/7=3 equation: 



(b-5)/7=3

We move all terms to the left:

(b-5)/7-(3)=0

We multiply all the terms by the denominator


(b-5)-3*7=0

We add all the numbers together, and all the variables

(b-5)-21=0

We get rid of parentheses

b-5-21=0

We add all the numbers together, and all the variables

b-26=0

We move all terms containing b to the left, all other terms to the right

b=26

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