(b-4)(b+4)=0

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Solution for (b-4)(b+4)=0 equation:


Simplifying
(b + -4)(b + 4) = 0

Reorder the terms:
(-4 + b)(b + 4) = 0

Reorder the terms:
(-4 + b)(4 + b) = 0

Multiply (-4 + b) * (4 + b)
(-4(4 + b) + b(4 + b)) = 0
((4 * -4 + b * -4) + b(4 + b)) = 0
((-16 + -4b) + b(4 + b)) = 0
(-16 + -4b + (4 * b + b * b)) = 0
(-16 + -4b + (4b + b2)) = 0

Combine like terms: -4b + 4b = 0
(-16 + 0 + b2) = 0
(-16 + b2) = 0

Solving
-16 + b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + b2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + b2 = 0 + 16
b2 = 0 + 16

Combine like terms: 0 + 16 = 16
b2 = 16

Simplifying
b2 = 16

Take the square root of each side:
b = {-4, 4}

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