(b-3)/4=(b+7)/3

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Solution for (b-3)/4=(b+7)/3 equation: 



(b-3)/4=(b+7)/3

We move all terms to the left:

(b-3)/4-((b+7)/3)=0

We calculate fractions


b/()+(-((b+7)*4)/()=0



We calculate terms in parentheses: +(-((b+7)*4)/(), so:

-((b+7)*4)/(

We multiply all the terms by the denominator


-((b+7)*4)



We calculate terms in parentheses: -((b+7)*4), so:

(b+7)*4

We multiply parentheses

4b+28

Back to the equation:

-(4b+28)



We get rid of parentheses

-4b-28

Back to the equation:

+(-4b-28)



We get rid of parentheses

b/()-4b-28=0

We multiply all the terms by the denominator


b-4b*()-28*()=0

We add all the numbers together, and all the variables

b-4b*()=0

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