(b-3)(b-4)=

Solution for (b-3)(b-4)= equation:

Simplifying
(b + -3)(b + -4) = 0

Reorder the terms:
(-3 + b)(b + -4) = 0

Reorder the terms:
(-3 + b)(-4 + b) = 0

Multiply (-3 + b) * (-4 + b)
(-3(-4 + b) + b(-4 + b)) = 0
((-4 * -3 + b * -3) + b(-4 + b)) = 0
((12 + -3b) + b(-4 + b)) = 0
(12 + -3b + (-4 * b + b * b)) = 0
(12 + -3b + (-4b + b2)) = 0

Combine like terms: -3b + -4b = -7b
(12 + -7b + b2) = 0

Solving
12 + -7b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(3 + -1b)(4 + -1b) = 0

Subproblem 1
Set the factor '(3 + -1b)' equal to zero and attempt to solve:

Simplifying
3 + -1b = 0

Solving
3 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 0 + -3
-1b = 0 + -3

Combine like terms: 0 + -3 = -3
-1b = -3

Divide each side by '-1'.
b = 3

Simplifying
b = 3
Subproblem 2
Set the factor '(4 + -1b)' equal to zero and attempt to solve:

Simplifying
4 + -1b = 0

Solving
4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1b = 0 + -4
-1b = 0 + -4

Combine like terms: 0 + -4 = -4
-1b = -4

Divide each side by '-1'.
b = 4

Simplifying
b = 4
Solution
b = {3, 4}