(b-2)/3=(3b-11)/4

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Solution for (b-2)/3=(3b-11)/4 equation: 


b in (-oo:+oo)

(b-2)/3 = (3*b-11)/4 // - (3*b-11)/4

(b-2)/3-((3*b-11)/4) = 0

(b-2)/3+(-1*(3*b-11))/4 = 0

(4*(b-2))/(3*4)+(-1*3*(3*b-11))/(3*4) = 0

4*(b-2)-1*3*(3*b-11) = 0

25-5*b = 0

(25-5*b)/(3*4) = 0

(25-5*b)/(3*4) = 0 // * 3*4

25-5*b = 0

25-5*b = 0 // - 25

-5*b = -25 // : -5

b = -25/(-5)

b = 5

b = 5

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